Modular Exponentiation 3^6mod11

Solve 36 mod 11 using: Modular exponentiation n is our exponent = 6 y = 1 and u 3 mod 11 = 3 See here Since 6 is even, we keep y = 1 u2 mod p = 32 mod 11 u2 mod p = 9 mod 11 9 mod 11 = 9Reset u

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Enter Modular Exponentiation

Solve 36 mod 11 using:

Modular exponentiation

Build an algorithm:

n is our exponent = 6

y = 1 and u ≡ 3 mod 11 = 3

See here

n = 6 is even

Since 6 is even, we keep y = 1

Determine u2 mod p

u2 mod p = 32 mod 11

u2 mod p = 9 mod 11

9 mod 11 = 9
Reset u to this value

Cut n in half and take the integer

6 ÷ 2 = 3

n = 3 is odd

Since 3 is odd, calculate (y)(u) mod p

(y)(u) mod p = (1)(9) mod 11

(y)(u) mod p = 9 mod 11

9 mod 11 = 9
Reset y to this value

Determine u2 mod p

u2 mod p = 92 mod 11

u2 mod p = 81 mod 11

81 mod 11 = 4
Reset u to this value

Cut n in half and take the integer

3 ÷ 2 = 1

n = 1 is odd

Since 1 is odd, calculate (y)(u) mod p

(y)(u) mod p = (9)(4) mod 11

(y)(u) mod p = 36 mod 11

36 mod 11 = 3
Reset y to this value

Determine u2 mod p

u2 mod p = 42 mod 11

u2 mod p = 16 mod 11

16 mod 11 = 5
Reset u to this value

Cut n in half and take the integer

1 ÷ 2 = 0

Because n = 0, we stop

We have our answer

Final Answer

36 mod 11 ≡ 3


What is the Answer?

36 mod 11 ≡ 3

How does the Modular Exponentiation and Successive Squaring Calculator work?

Free Modular Exponentiation and Successive Squaring Calculator - Solves xn mod p using the following methods:
* Modular Exponentiation
* Successive Squaring
This calculator has 1 input.

What 1 formula is used for the Modular Exponentiation and Successive Squaring Calculator?

Successive Squaring I = number of digits in binary form of n. Run this many loops of a2 mod p

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What 6 concepts are covered in the Modular Exponentiation and Successive Squaring Calculator?

exponentThe power to raise a numberintegera whole number; a number that is not a fraction
...,-5,-4,-3,-2,-1,0,1,2,3,4,5,...modular exponentiationthe remainder when an integer b (the base) is raised to the power e (the exponent), and divided by a positive integer m (the modulus)modulusthe remainder of a division, after one number is divided by another.
a mod bremainderThe portion of a division operation leftover after dividing two integerssuccessive squaringan algorithm to compute in a finite field

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